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Fix PostgreSQL password escaping
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Browse source 
Use SQL-standard single quote doubling instead of psql variable
syntax which doesn't work with -c flag.

🤖 Generated with [Claude Code](https://claude.com/claude-code)

Co-Authored-By: Claude Opus 4.5 <noreply@anthropic.com>
This commit is contained in:
Patrick Mulligan 2026-01-11 20:10:21 +01:00
parent dcc376a775
commit 047191835c
1 changed files with 3 additions and 1 deletions
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4
modules/lamassu-lnbits.nix
View file

@ -253,7 +253,9 @@ in
for i in {1..30}; do for i in {1..30}; do
if ${pkgs.postgresql}/bin/psql -tAc "SELECT 1 FROM pg_roles WHERE rolname='${cfg.database.user}'" | grep -q 1; then if ${pkgs.postgresql}/bin/psql -tAc "SELECT 1 FROM pg_roles WHERE rolname='${cfg.database.user}'" | grep -q 1; then
password=$(cat ${secretsDir}/lamassu-db-password) password=$(cat ${secretsDir}/lamassu-db-password)
${pkgs.postgresql}/bin/psql -v password="$password" -c "ALTER USER \"${cfg.database.user}\" WITH PASSWORD :'password';" # Escape single quotes by doubling them (SQL standard)
escaped_password=$(printf '%s' "$password" | sed "s/'/''/g")
${pkgs.postgresql}/bin/psql -c "ALTER USER \"${cfg.database.user}\" WITH PASSWORD '$escaped_password';"
exit 0 exit 0
fi fi
sleep 1 sleep 1